17*x^2-10*x-48=0

Solution for 17*x^2-10*x-48=0 equation:

17x^2-10x-48=0

a = 17; b = -10; c = -48;
Δ = b2-4ac
Δ = -102-4·17·(-48)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-58}{2*17}=\frac{-48}{34}
=-1+7/17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+58}{2*17}=\frac{68}{34}
=2
$